{"id":6665,"date":"2021-02-23T10:46:46","date_gmt":"2021-02-23T09:46:46","guid":{"rendered":"https:\/\/steamerproject.eu\/grain\/4-14\/"},"modified":"2021-03-11T17:47:03","modified_gmt":"2021-03-11T16:47:03","slug":"4-14","status":"publish","type":"grain","link":"https:\/\/steamerproject.eu\/lv\/nodarb\u012bba\/4-14\/","title":{"rendered":"Atv\u0113rt\u0101 ce\u013ca m\u012bklas &#8211; 4. Noda\u013ca 14. Nodarb\u012bba"},"content":{"rendered":"\n<p>Iepriek\u0161\u0113j\u0101 nodarb\u012bb\u0101 m\u0113s apl\u016bkoj\u0101m plusus un m\u012bnusus izlau\u0161an\u0101s sp\u0113l\u0113m, kas veidotas p\u0113c line\u0101r\u0101 ce\u013ca principa. \u0160aj\u0101 sada\u013c\u0101 iepaz\u012bstin\u0101sim ar otro sp\u0113les strukt\u016bras veidu, ko aprakst\u012bjis Nikolsons (2015): atv\u0113rto ce\u013cu.<\/p>\n\n<p>Atv\u0113rto ce\u013cu veido m\u012bklas, kuras var atrisin\u0101t jebkur\u0101 sec\u012bb\u0101 (Wiemker et al., 2015). Visas m\u012bklas, iz\u0146emot p\u0113d\u0113jo, ir pieejamas atrisin\u0101\u0161anai jau no sp\u0113les s\u0101kuma. Katrs sp\u0113l\u0113t\u0101js var izv\u0113l\u0113ties, uz kuru fokus\u0113ties, un vi\u0146am ir iesp\u0113ja pa\u0146emt p\u0101rtraukumu un atgriezties pie t\u0101s v\u0113l\u0101k. P\u0113d\u0113j\u0101 m\u012bkla &#8211; ko bie\u017ei d\u0113v\u0113 par meta-m\u012bklu &#8211; parasti tiek sl\u0113pta, un pie t\u0101s nevar str\u0101d\u0101t, kam\u0113r nav pabeigtas p\u0101r\u0113j\u0101s m\u012bklas. Nor\u0101des t\u0101s atrisin\u0101\u0161anai parasti izriet no iepriek\u0161 ieg\u016btaj\u0101m atbild\u0113m. (Wiemker et al., 2015). Katras s\u0101kotn\u0113j\u0101s m\u012bklas risin\u0101jums satur jaunas m\u012bklas da\u013cas, kas j\u0101apvieno, lai tiktu atrisin\u0101ta meta-m\u012bkla.<\/p>\n\n<h2><strong>Ilustr\u0101cija<\/strong><\/h2>\n\n<p>\u0160\u012b infografika no Wiemker et al. (2015) var\u0113tu pal\u012bdz\u0113t jums vizualiz\u0113t, ko m\u0113s dom\u0101jam ar atv\u0113rto ce\u013cu.<\/p>\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" width=\"580\" height=\"276\" src=\"https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-111.png\" alt=\"\" class=\"wp-image-4058\" srcset=\"https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-111.png 580w, https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-111-480x228.png 480w\" sizes=\"(min-width: 0px) and (max-width: 480px) 480px, (min-width: 481px) 580px, 100vw\" \/><figcaption>Extracted from Wiemker et al. (2015, p.9).<\/figcaption><\/figure><\/div>\n\n<p>Ies\u0101kum\u0101 mums ir \u010detri da\u017e\u0101di uzdevumi: sl\u0113dzene, kaste, aizv\u0113rtas durvis un l\u0101de. Katrs tiem ir j\u0101atver sav\u0101 laik\u0101 un atsevi\u0161\u0137i. Katram no tiem ir nepiecie\u0161ama m\u012bkla. Katr\u0101 no t\u0101m parasti sl\u0113pjas jaunas m\u012bklas vai meta-m\u012bklas risin\u0101juma da\u013cas. \u0160eit t\u0101s ir atsl\u0113gas da\u013ca, kuras visas ir j\u0101apvieno, lai atv\u0113rtu izejas durvis.<\/p>\n\n<p>T\u0101l\u0101k apl\u016bkosim divus meta-m\u012bklas piem\u0113rus, ko var\u0113tu izmantot STEM:<\/p>\n\n<ul><li>Matem\u0101tik\u0101 m\u0113s varam iedom\u0101ties vien\u0101dojuma da\u013cas, kuras b\u016btu j\u0101apvieno un p\u0113c tam j\u0101atrisina, lai atv\u0113rtu sl\u0113dzeni uz izejas durv\u012bm.<\/li><li>\u0136\u012bmij\u0101 m\u0113s varam iedom\u0101ties sagrieztu molekulu, kas b\u016btu j\u0101atjauno. \u0136\u012bmisk\u0101 formula var\u0113tu b\u016bt kods, lai atv\u0113rtu kripteksu, kur\u0101 ir durvju atsl\u0113ga (piem\u0113ram, izmantojot NaCl apz\u012bm\u0113jumu n\u0101trija hlor\u012bdam vai C6H12O6 glikozei).<\/li><\/ul>\n<p><em>Kriptekss <\/em>ir p\u0101rn\u0113s\u0101jama glab\u0101tuve, kas pirmo reizi par\u0101d\u012bj\u0101s 2003. gad\u0101 Dena Brauna &#8220;Da Vin\u010di Kod\u0101&#8221; (Cryptex, 2019). To apg\u016bt ir viegl\u0101k nek\u0101 \u0161\u0137iet. To var izveidot m\u0101j\u0101s ar kartona un pap\u012bra, ja j\u016bs varat velt\u012bt tam mazliet laika. (Nadam, 2019) Gatav\u0101s plastmasas versijas var ieg\u0101d\u0101ties ar\u012b tie\u0161saist\u0113. Jums b\u016bs nepiecie\u0161ams tikai to iestat\u012bt.<\/p>\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" width=\"500\" height=\"281\" src=\"https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-112.png\" alt=\"\" class=\"wp-image-4064\" srcset=\"https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-112.png 500w, https:\/\/steamerproject.eu\/wp-content\/uploads\/2021\/02\/image-112-480x270.png 480w\" sizes=\"(min-width: 0px) and (max-width: 480px) 480px, (min-width: 481px) 500px, 100vw\" \/><figcaption>Patrice Nadam on S\u2019cape, <a href=\"https:\/\/scape.enepe.fr\/cryptex.html\">https:\/\/scape.enepe.fr\/cryptex.html<\/a><\/figcaption><\/figure><\/div>\n\n<h2><strong>Plusi<\/strong><\/h2>\n\n<p>\u0160is ce\u013c\u0161 nav visizplat\u012bt\u0101kais vis\u0101 pasaul\u0113. Nikolsons (2015) to atrada tikai 13% no 175 apsekotajiem objektiem. Tom\u0113r tas ir vair\u0101k piel\u0101gots izgl\u012btojo\u0161\u0101m izlau\u0161an\u0101s istab\u0101m nek\u0101 line\u0101rais ce\u013c\u0161. K\u0101 m\u0113s jau min\u0113j\u0101m iepriek\u0161, izgl\u012btojo\u0161\u0101s izlau\u0161an\u0101s sp\u0113l\u0113s parasti tiek grup\u0113ti l\u012bdz 10 skol\u0113niem vien\u0101 grup\u0101, kas ir p\u0101r\u0101k daudz, lai line\u0101r\u0101 strukt\u016bra izr\u0101d\u012btos efekt\u012bva. Atv\u0113rtais ce\u013c\u0161 \u013cauj vienlaikus risin\u0101\u0161anas proces\u0101 iesaist\u012bt vair\u0101k cilv\u0113ku. Wiemker\u2019s et al. iepriek\u0161 min\u0113taj\u0101 piem\u0113r\u0101 divi skol\u0113ni var\u0113tu m\u0113\u0123in\u0101t atrisin\u0101t ar sl\u0113dzeni saist\u012bto m\u012bklu, tr\u012bs citi m\u0113\u0123in\u0101tu atv\u0113rt l\u0101di utt.<\/p>\n\n<p>Pirmk\u0101rt, tas veicin\u0101s sadarb\u012bbu:<\/p>\n\n<ol><li>gan mazaj\u0101s grup\u0101s, kas str\u0101d\u0101 pie katras s\u0101kotn\u0113j\u0101s m\u012bklas;<\/li><li>gan starp mazaj\u0101m grup\u0101m, lai atrisin\u0101tu gala uzdevumu. Dal\u012bbniekiem b\u016bs j\u0101dal\u0101s ar sav\u0101m idej\u0101m, atkl\u0101jumiem un dom\u0101\u0161anas gaitu.<\/li><\/ol>\n<p>Turkl\u0101t, ja viena grupa pabeidz savu m\u012bklu pirms otras, pirm\u0101s grupas skol\u0113ni var\u0113tu pal\u012bdz\u0113t klasesbiedriem atrisin\u0101t vi\u0146u m\u012bklu. Ja divas grupas ir iestr\u0113gu\u0161as pat p\u0113c tam, kad ir doti m\u0101jieni, skol\u0113ni var apmain\u012bties ar m\u012bkl\u0101m un viens otram pied\u0101v\u0101t jaunu perspekt\u012bvu.<\/p>\n\n<p>Atv\u0113rt\u0101s strukt\u016bras priek\u0161roc\u012bba ir ar\u012b t\u0101, ka to ir viegli uztais\u012bt. Da\u017eos gad\u012bjumos tas var izr\u0101d\u012bties pat viegl\u0101k nek\u0101 izveidot line\u0101r\u0101 ce\u013ca strukt\u016bru, jo tas neprasa p\u0101rdom\u0101t m\u012bklu sec\u012bbu.<\/p>\n\n<h2><strong>M\u012bnusi<\/strong><\/h2>\n\n<p>Pirmais m\u012bnuss ir saist\u012bts ar gr\u016bt\u012bbas pak\u0101pi.<\/p>\n\n<p>Pirmk\u0101rt, nepieredz\u0113ju\u0161iem sp\u0113l\u0113t\u0101jiem atv\u0113rto ce\u013cu b\u016bs gr\u016bt\u0101k iziet, jo \u0161ai m\u012bklu strukt\u016brai tr\u016bkst skaidra s\u0101kuma punkta, k\u0101 ar\u012b redzamas sec\u012bbas un lo\u0123ikas. Tas var\u0113tu rad\u012bt neskaidr\u012bbas starp skol\u0113niem, it \u012bpa\u0161i jaun\u0101kajiem.<\/p>\n\n<p>Tom\u0113r \u0161o probl\u0113mu var atrisin\u0101t ar saprotamu paskaidrojumu no sp\u0113les vad\u012bt\u0101ja \/ pedagoga puses pirms sp\u0113les s\u0101kuma, vai ar da\u017eiem nor\u0101d\u012bjumiem, kas sniegti vai nu pa\u0161\u0101 s\u0101kum\u0101, vai ar\u012b br\u012bd\u012b, kad skol\u0113ni iestr\u0113gst pie k\u0101das m\u012bklas uz vair\u0101k\u0101m min\u016bt\u0113m.<\/p>\n\n<p>Otrk\u0101rt, atv\u0113rtie ce\u013ci var\u0113tu \u0161\u0137ist p\u0101r\u0101k viegli un neinteresanti skol\u0113niem, kuri jau iepriek\u0161 ir sp\u0113l\u0113ju\u0161i profesion\u0101l\u0101s izlau\u0161an\u0101s sp\u0113les. Atv\u0113rtie ce\u013ci nedod iesp\u0113ju sag\u0101d\u0101t p\u0101rsteigumus, jo viss ir pieejams jau no pa\u0161a s\u0101kuma. Pieredz\u0113ju\u0161i sp\u0113l\u0113t\u0101ji zin\u0101s, ko dar\u012bt. Tom\u0113r nenoteikt\u012bba un atkl\u0101\u0161ana ir divi b\u016btiski izlau\u0161an\u0101s sp\u0113les main\u012bgie. T\u0101p\u0113c, ja m\u012bklas neseko viena otrai, tas var\u0113tu mazin\u0101t gandar\u012bjuma saj\u016btu un rad\u012bt garlaic\u012bbu.<\/p>\n\n<p>\u0145emot v\u0113r\u0101 \u0161o kontekstu, m\u0113s iesak\u0101m izmantot atv\u0113rto ce\u013cu sava rad\u012b\u0161anas procesa vid\u016b p\u0113c line\u0101r\u0101 ce\u013ca p\u0101rbaudes. Ja tas atbilst j\u016bsu un j\u016bsu skol\u0113nu vajadz\u012bb\u0101m, tad t\u0101 ar\u012b turpiniet. Ja t\u0101 nenotiek, pak\u0101peniski att\u0101linieties no t\u0101, kad ieg\u016bstat p\u0101rliec\u012bbu.<\/p>\n\n<p>V\u0113l viens iesp\u0113jamais ce\u013c\u0161 b\u016bs aprakst\u012bts n\u0101kamaj\u0101 noda\u013c\u0101. Tas dos jums jaunu risin\u0101jumu &#8211; gr\u016bt\u0101ku, bet saisto\u0161\u0101ku -, lai izvair\u012btos no iepriek\u0161 min\u0113taj\u0101m probl\u0113m\u0101m un izveidotu sare\u017e\u0123\u012btu m\u012bklu sec\u012bbu.<\/p>\n","protected":false},"featured_media":0,"template":"","gender":[],"steam":[],"acf":[],"_links":{"self":[{"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/grain\/6665"}],"collection":[{"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/grain"}],"about":[{"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/types\/grain"}],"wp:attachment":[{"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/media?parent=6665"}],"wp:term":[{"taxonomy":"gender","embeddable":true,"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/gender?post=6665"},{"taxonomy":"steam","embeddable":true,"href":"https:\/\/steamerproject.eu\/lv\/wp-json\/wp\/v2\/steam?post=6665"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}